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Q.
Hydrolysis of $BCl_3$ gives $X$, which on treatment with sodium carbonate produces $Y, X$ and $Y$, respectively, are
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Solution:
Hydrolysis of $BCl_3$ gives boric acid $(X)$, which on treatment with sodium carbonate produces sodium metaborate $(F)$, carbon dioxide and water
$BCl _{3}+3 H _{2} O \longrightarrow H _{3} \underset{X}{ B } O _{3}+3 HCl$
$4 H _{3} BO _{3}+ Na _{2} CO _{3} \longrightarrow $
$\underset{Y}{Na _{2} B _{4} O _{7}}+ CO _{2}+6 H _{2} O$