Hydrogen (a moles) and iodine (b moles) react to give 2 x moles of the H I at equilibrium. The total number of moles at equilibrium is

Question

Hydrogen (a moles) and iodine (b moles) react to give 2 x moles of the H I at equilibrium. The total number of moles at equilibrium is (A) a+b+2 x (B) (a-b)+(b-2 x) (C) ( a + b ) (D) a+b-x

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/a5f9e51c5fb889f7035d5295d803ce3c-.png" /> ∴ Total moles = a +b

Q. Hydrogen ( $a$ moles) and iodine ( $b$ moles) react to give $2 x$ moles of the $H I$ at equilibrium. The total number of moles at equilibrium is

$a + b + 2 x$

$(a - b) + (b - 2 x)$

$(a + b)$

$a + b - x$

$∴$ Total moles $= a + b$

Q. Hydrogen (a moles) and iodine (b moles) react to give 2x moles of the HI at equilibrium. The total number of moles at equilibrium is

a+b+2x

(a−b)+(b−2x)

(a+b)

a+b−x