Question

Hybridisation states of $C$ in $C{H}_3^{+}$ and $C{H}_4$ are

• A. $s{p}^2$ & $s{p}^3$
• B. $s{p}^3$ & $s{p}^2$
• C. $s{p}^2$ & $s{p}^2$
• D. $s{p}^3$ & $s{p}^3$

Answer 1

Answer: (A)

Number of sigma bonds in $\stackrel{+}{C}{H}_3$ are $3$ , thus, hybridisation is $s{p}^2$.
Number of sigma bonds in $C{H}_4$ are $4$ , thus, hybridisation is $s{p}^3$.