Question

Hybridisation and structure of $Xe{F}_2$ is

• A. $s{p}^3{d}^2$, square planar
• B. $s{p}^3$, tetrahedral
• C. $s{p}^{3}d$, trigonal bipyramidal
• D. $s{p}^3{d}^2$, hexagonal

Answer 1

Answer: (C)

$Xe{F}_2$ has trigonal bipyramidal geometry due to $s{p}^{3}d$ hybridisation of $Xe$. Three equatorial positions are occupied by lone pairs of electrons giving a linear shape to the molecule.