Question

How will the rate of reaction, $2NO+O_2\to 2N{O}_2$ change, if the volume of the reaction vessel is doubled?

• A. It will diminish to 1/4 of the initial value
• B. It will diminish to 1/8 of the initial value
• C. It will grow four times
• D. It will grow eight times

Answer 1

Answer: (B)

When volume is doubled, concentration are halved. Hence, new rate $=k{\left(\frac{a}{2}\right)}^2\left(\frac{b}{2}\right)=\frac{1}{8}K{a}^{2}b$ i.e. it is $\frac{1}{8}$ th of the initial value.