Question

How much sulphur is present in organic compound if on analysis 0.64 g of this compound gives 2.248 g of $BaS{O}_4$?

• A. 46%
• B. 48%
• C. 50%
• D. 40%

Answer 1

Answer: (B)

% of sulphur
$=\frac{32}{233}\times \frac{MassofBaS{O}_{4}formed}{Massoforganiccompound}\times 100$
$=\frac{32}{233}\times \frac{2.248}{233}\times 100=48.24\%$