How much mass of sodium acetate is required to make 250 mL of 0.575 molar aqueous solution?

Question

How much mass of sodium acetate is required to make 250 mL of 0.575 molar aqueous solution? (A) 11.79 g (B) 15.38 g (C) 10.81 g (D) 25.35 g

Tardigrade Admin · Accepted Answer

Molar mass of sodium acetate (CH3COONa) = 82.0245 g/mol Mass of CH3COONa required to make 250 mL of 0.575 M solution = (0.575× 82.0245 × 250/1000) = 11.79 g

Q. How much mass of sodium acetate is required to make $250 m L$ of $0.575$ molar aqueous solution?

$11.79 g$

$15.38 g$

$10.81 g$

$25.35 g$

Molar mass of sodium acetate $(C H_{3} COON a)$
$= 82.0245 g / m o l$
Mass of $C H_{3} COON a$ required to make $250 m L$ of
$0.575 M$ solution $= \frac{0.575 \times 82.0245 \times 250}{1000} = 11.79 g$

Q. How much mass of sodium acetate is required to make 250mL of 0.575 molar aqueous solution?

11.79g

15.38g

10.81g

25.35g