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Q.
How much mass of sodium acetate is required to make $250\,mL$ of $0.575$ molar aqueous solution?
Some Basic Concepts of Chemistry
Solution:
Molar mass of sodium acetate $(CH_{3}COONa)$
$ = 82.0245 \,g/mol $
Mass of $CH_{3}COONa$ required to make $250 \,mL$ of
$0.575\,M$ solution $= \frac{0.575\times 82.0245 \times 250}{1000} = 11.79\,g$