How much mass of silver nitrate will react with 5.85 g of sodium chloride to produce 14.35 g of silver chloride and 8.5 g of sodium nitrate if law of conservation of mass is followed?

Question

How much mass of silver nitrate will react with 5.85 g of sodium chloride to produce 14.35 g of silver chloride and 8.5 g of sodium nitrate if law of conservation of mass is followed? (A) 22.85 g (B) 108 g (C) 17.0 g (D) 28.70 g

Tardigrade Admin · Accepted Answer

underset text x AgNO 3+ underset5.85 g NaCl longrightarrow underset8.5 g NaNO 3+ underset14.35 g AgCl x + 5.85 = 8.5 + 14 .35 ⇒ x = 17 g

Q. How much mass of silver nitrate will react with $5.85 g$ of sodium chloride to produce $14.35 g$ of silver chloride and $8.5 g$ of sodium nitrate if law of conservation of mass is followed?

$22.85 g$

$108 g$

$17.0 g$

$28.70 g$

$x A g N O_{3} + 5.85 g N a Cl ⟶ 8.5 g N a N O_{3} + 14.35 g A g Cl$
$x + 5.85 = 8.5 + 14.35$
$\Rightarrow x = 17 g$

Q. How much mass of silver nitrate will react with 5.85g of sodium chloride to produce 14.35g of silver chloride and 8.5g of sodium nitrate if law of conservation of mass is followed?

22.85g

108g

17.0g

28.70g