How much energy is absorbed by 10 kg molecule of an ideal gas, if it expands from an initial pressure of 8 atm to 4 atm at a constant temperature of 27° C ?

Question

How much energy is absorbed by 10 kg molecule of an ideal gas, if it expands from an initial pressure of 8 atm to 4 atm at a constant temperature of 27° C ? (A)  1.728× 107J  (B)  2.8× 106J  (C)  5J  (D)  10J

Tardigrade Admin · Accepted Answer

Q = work done by the gas Q=μ RT log e( (p1/p2) ) Q=(10× 1000 text mol)× (8.31) × 300× log e( (8/4) ) Q=104× 8.31× 300× 2.302× 0.301 Q=1.728× 107J

Q. How much energy is absorbed by 10 kg molecule of an ideal gas, if it expands from an initial pressure of 8 atm to 4 atm at a constant temperature of $27^{\circ} C$ ?

$1.728 \times 10^{7} J$

$2.8 \times 10^{6} J$

$5 J$

$10 J$

$15 J$

Q = work done by the gas $Q = μ RT lo g_{e} (\frac{p _{1}}{p _{2}})$ $Q = (10 \times 1000 m o l) \times (8.31)$ $\times 300 \times lo g_{e} (\frac{8}{4})$ $Q = 10^{4} \times 8.31 \times 300 \times 2.302 \times 0.301$ $Q = 1.728 \times 10^{7} J$

Q. How much energy is absorbed by 10 kg molecule of an ideal gas, if it expands from an initial pressure of 8 atm to 4 atm at a constant temperature of 27∘C ?

1.728×107J

2.8×106J

5J

10J

15J

Q = work done by the gas Q=μRTloge​(p2​p1​​) Q=(10×1000mol)×(8.31) ×300×loge​(48​) Q=104×8.31×300×2.302×0.301 Q=1.728×107J