How much amount of NaCl should be added to 600 g of water (ρ = 1.00 g/mL) to decrease the freezing point of water to — 0.2°C ? . (The freezing point depression constant for water = 2 K kg mol-1) Given --

Question

How much amount of NaCl should be added to 600 g of water (ρ = 1.00 g/mL) to decrease the freezing point of water to — 0.2°C ? . (The freezing point depression constant for water = 2 K kg mol-1) Given -- (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Δ Tf=i× m× Kf 0.2=2×2×(w/ 58.5/600/ 1000) w=1.755 gm

Q. How much amount of NaCl should be added to 600 g of water ( $ρ$ = 1.00 g/mL) to decrease the freezing point of water to — 0.2 $^{\circ}$ C ? ____________________ . (The freezing point depression constant for water = 2 K kg mol $^{- 1}$ )
Given --

$Δ T_{f} = i \times m \times K_{f}$
$0.2 = 2 \times 2 \times \frac{w /58.5}{600/1000}$
$w = 1.755 g m$

Q. How much amount of NaCl should be added to 600 g of water (ρ = 1.00 g/mL) to decrease the freezing point of water to — 0.2∘C ? ____________________ . (The freezing point depression constant for water = 2 K kg mol−1) Given --

ΔTf​=i×m×Kf​ 0.2=2×2×600/1000w/58.5​ w=1.755gm

Q. How much amount of NaCl should be added to 600 g of water ( $ρ$ = 1.00 g/mL) to decrease the freezing point of water to — 0.2 $^{\circ}$ C ? ____________________ . (The freezing point depression constant for water = 2 K kg mol $^{- 1}$ )
Given --

$Δ T_{f} = i \times m \times K_{f}$
$0.2 = 2 \times 2 \times \frac{w /58.5}{600/1000}$
$w = 1.755 g m$