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Question
Chemistry
How much amount of CuSO4 ⋅ 5H2O is required for liberation of 2.54 g of I2 when titrated with KI ?
Q. How much amount of
C
u
S
O
4
⋅
5
H
2
O
is required for liberation of 2.54 g of
I
2
when titrated with KI ?
2363
180
AIIMS
AIIMS 2011
Some Basic Concepts of Chemistry
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A
2.5 g
14%
B
4.99 g
64%
C
2.4 g
14%
D
1.2 g
8%
Solution:
2
C
u
S
O
4
⋅
5
H
2
O
+
4
K
I
→
C
u
2
I
2
+
2
K
2
S
O
4
+
254
g
I
2
+
10
H
2
O
Molecular weight of
2
C
u
S
O
4
⋅
5
H
2
O
[
2
(
63.5
+
32
+
64
)
+
10
(
18
)]
g
=
499
g
254
g
of
I
2
is liberated by
499
g
C
u
S
O
4
⋅
5
H
2
O
2.54
g
of
I
2
will be liberated by
x
g
C
u
S
O
4
⋅
5
H
2
O
x
=
254
499
×
2.54
=
4.99
g