How many stereoisomers does this molecule have? CH3CH=CHCH2CHBrCH3

Question

How many stereoisomers does this molecule have? CH3CH=CHCH2CHBrCH3 (A) 8 (B) 2 (C) 4 (D) 6

Tardigrade Admin · Accepted Answer

The given compound may be written as <img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/c-jotzocyburfijfje.jpg" /> Both geometrical isomerism (cis-trans form) and optical isomerism is possible in the given compound. Number of optical isomer =2n=21=2 (where n = number of asymmetric carbon) Hence total number of stereoisomers =2+2=4

Q. How many stereoisomers does this molecule have?
$C H_{3} C H = C H C H_{2} C H B r C H_{3}$

8

2

4

6

The given compound may be written as

Both geometrical isomerism (cis-trans form) and optical isomerism is possible in the given compound.
Number of optical isomer $= 2^{n} = 2^{1} = 2$
(where n = number of asymmetric carbon)
Hence total number of stereoisomers $= 2 + 2 = 4$

Q. How many stereoisomers does this molecule have? CH3​CH=CHCH2​CHBrCH3​

8

2

4

6

The given compound may be written as Both geometrical isomerism (cis-trans form) and optical isomerism is possible in the given compound. Number of optical isomer =2n=21=2 (where n = number of asymmetric carbon) Hence total number of stereoisomers =2+2=4

Q. How many stereoisomers does this molecule have?
$C H_{3} C H = C H C H_{2} C H B r C H_{3}$

The given compound may be written as

Both geometrical isomerism (cis-trans form) and optical isomerism is possible in the given compound.
Number of optical isomer $= 2^{n} = 2^{1} = 2$
(where n = number of asymmetric carbon)
Hence total number of stereoisomers $= 2 + 2 = 4$