How many optically active stereoisomers are possible for butane-2, 3-diol?

Question

How many optically active stereoisomers are possible for butane-2, 3-diol? (A) 0 (B) 1 (C) 2 (D) 3

Tardigrade Admin · Accepted Answer

The structure of butane-2, 3-diol is as: CH3- underset beginsmallmatrix | OH endsmallmatrix overset beginsmallmatrix H | endsmallmatrix mathopC* - underset beginsmallmatrix | OH endsmallmatrix overset beginsmallmatrix H | endsmallmatrix mathopC* -CH3 ∵ Optical isomers in compounds have similar asymmetric carbon atom, which are even in number =2n-1 Here, n=2 ∴ total number of optically active stereoisomers =22-1=3

Q. How many optically active stereoisomers are possible for butane-2, 3-diol?

0

1

2

3

4

The structure of butane-2, 3-diol is as
: $C H_{3} - ∣ O H C^{} H ∣ - ∣ O H C^{} H ∣ - C H_{3}$
$∵$ Optical isomers in compounds have similar asymmetric carbon atom, which are even in number $= 2^{n} - 1$ Here, $n = 2$ $∴$ total number of optically active stereoisomers $= 2^{2} - 1 = 3$

Q. How many optically active stereoisomers are possible for butane-2, 3-diol?

0

1

2

3

4

The structure of butane-2, 3-diol is as : CH3​−∣OH​C∗H∣​​−∣OH​C∗H∣​​−CH3​ ∵ Optical isomers in compounds have similar asymmetric carbon atom, which are even in number =2n−1 Here, n=2 ∴ total number of optically active stereoisomers =22−1=3

The structure of butane-2, 3-diol is as
: $C H_{3} - ∣ O H C^{} H ∣ - ∣ O H C^{} H ∣ - C H_{3}$
$∵$ Optical isomers in compounds have similar asymmetric carbon atom, which are even in number $= 2^{n} - 1$ Here, $n = 2$ $∴$ total number of optically active stereoisomers $= 2^{2} - 1 = 3$