How many of the given reaction will form tert-Butyl ethyl ether (I) tert - Butanol + Ethanol xrightarrowH+ (II) tert-Butyl bromide + Sodium ethoxide → (III) Sodium tert-butoxide + Ethyl bromide → (IV) Isobutene + Ethanol xrightarrowH+

Question

How many of the given reaction will form tert-Butyl ethyl ether (I) tert - Butanol + Ethanol xrightarrowH+ (II) tert-Butyl bromide + Sodium ethoxide → (III) Sodium tert-butoxide + Ethyl bromide → (IV) Isobutene + Ethanol xrightarrowH+  (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

(CH3)3CBr+NaOC2H5 can ’t be applied for synthesising the ether because sod. ethoxide, being a strong base, will preferentially cause elimination reaction (CH3)3CBr xrightarrow -OC2H5 (CH3)2C = CH2+HBr Rest other forms tert-Butyl ethyl ether

Q. How many of the given reaction will form tert-Butyl ethyl ether (I) tert - Butanol + Ethanol HX+​ (II) tert-Butyl bromide + Sodium ethoxide → (III) Sodium tert-butoxide + Ethyl bromide → (IV) Isobutene + Ethanol HX+​

(CH3​)3​CBr+NaOC2​H5​ can ’t be applied for synthesising the ether because sod. ethoxide, being a strong base, will preferentially cause elimination reaction (CH3​)3​CBrX−​X22−​OCX2​HX5​​(CH3​)2​C=CH2​+HBr Rest other forms tert-Butyl ethyl ether

Q. How many of the given reaction will form tert-Butyl ethyl ether
(I) tert - Butanol + Ethanol $H X^{+}$
(II) tert-Butyl bromide + Sodium ethoxide $\to$
(III) Sodium tert-butoxide + Ethyl bromide $\to$
(IV) Isobutene + Ethanol $H X^{+}$