Question

How many numbers greater than $40000$ can be formed from the digits $2,4,5,5,7$ ?

• A. 12
• B. 24
• C. 36
• D. 48

Answer 1

Answer: (D)

Number of permutations formed by given numbers $=\frac{5!}{2!}$ $=5\times 4\times 3=60$ Since, in these permutations numbers start with 2 are also included. Which will be less than 40000. If 2 be the starting digit, then the number of permutations formed by remaining four numbers $=\frac{4!}{2!}=4\times 3=12$
Hence, required permutations $=60-12=48$