How many no-bond resonating structures can be drawn for alkene having C 3 H 6 formula?

Question

How many no-bond resonating structures can be drawn for alkene having C 3 H 6 formula? (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

No. of hyperconjugation structures = No. of α-H atoms adjacent to sp 2 hybridized C-atom Three α-hydrogens are present in propene ( C 3 H 6). Thus, three no-bond resonating structures (or hyperconjugation structures) can be drawn for propene.

Q. How many no-bond resonating structures can be drawn for alkene having $C_{3} H_{6}$ formula?

No. of hyperconjugation structures $=$ No. of $α - H$ atoms adjacent to $s p^{2}$ hybridized $C$ -atom
Three $α$ -hydrogens are present in propene $(C_{3} H_{6})$ . Thus, three no-bond resonating structures (or hyperconjugation structures) can be drawn for propene.

Q. How many no-bond resonating structures can be drawn for alkene having C3​H6​ formula?

No. of hyperconjugation structures = No. of α−H atoms adjacent to sp2 hybridized C-atom Three α-hydrogens are present in propene (C3​H6​). Thus, three no-bond resonating structures (or hyperconjugation structures) can be drawn for propene.

Q. How many no-bond resonating structures can be drawn for alkene having $C_{3} H_{6}$ formula?

No. of hyperconjugation structures $=$ No. of $α - H$ atoms adjacent to $s p^{2}$ hybridized $C$ -atom
Three $α$ -hydrogens are present in propene $(C_{3} H_{6})$ . Thus, three no-bond resonating structures (or hyperconjugation structures) can be drawn for propene.