How many moles of nitrogen are needed to produce 8.2 moles of ammonia by reaction with hydrogen?

Question

How many moles of nitrogen are needed to produce 8.2 moles of ammonia by reaction with hydrogen? (A) 2.1 (B) 3.1 (C) 3.2 (D) 4.1

Tardigrade Admin · Accepted Answer

The balanced chemical equation is underset beginsmallmatrix 1 mol ? endsmallmatrix mathopN2 +3H2 xrightarrow[] underset beginsmallmatrix 2 mol 8.2 mol endsmallmatrix mathop2NH3 2 moles of NH3 are produced from N2=1 mol ∴ 8.2 moles of NH3 will be produced from N2 =(1/2)× 8.2 =4.1 text mol

Q. How many moles of nitrogen are needed to produce 8.2 moles of ammonia by reaction with hydrogen?

2.1

3.1

3.2

4.1

The balanced chemical equation is $1 m o l ? N_{2} + 3 H_{2} 2 m o l 8.2 m o l 2 N H_{3}$ 2 moles of $N H_{3}$ are produced from $N_{2} = 1$ mol $∴$ 8.2 moles of $N H_{3}$ will be produced from $N_{2}$ $= \frac{1}{2} \times 8.2$ $= 4.1 m o l$

Q. How many moles of nitrogen are needed to produce 8.2 moles of ammonia by reaction with hydrogen?

2.1

3.1

3.2

4.1

The balanced chemical equation is 1mol?​N2​​+3H2​​2mol8.2mol​2NH3​​ 2 moles of NH3​ are produced from N2​=1 mol ∴ 8.2 moles of NH3​ will be produced from N2​ =21​×8.2 =4.1mol

The balanced chemical equation is $1 m o l ? N_{2} + 3 H_{2} 2 m o l 8.2 m o l 2 N H_{3}$ 2 moles of $N H_{3}$ are produced from $N_{2} = 1$ mol $∴$ 8.2 moles of $N H_{3}$ will be produced from $N_{2}$ $= \frac{1}{2} \times 8.2$ $= 4.1 m o l$