Question

How many moles of $Mn{O}_4^{-}\&Ca(OH{)}_2$ are required to react with 1 mole of $Fe{\left(H{C}_2{O}_4\right)}_2$ respectively?

• A. 2, 1
• B. 3, 1
• C. 1 , 1
• D. 2, 2

Answer 1

Answer: (A)

$30H^{+}+5Mn{O}_4^{-}+5Fe{\left(H{C}_2{O}_4\right)}_2\to 5M{n}^{2+}+5F{e}^{3+}+$

$20C{O}_2+20H_{2}O$

From here it is evident that 1 mole of $5Mn{O}_4^{-}$ is required to react with 1 mole of $Fe{\left(H{C}_2{O}_4\right)}_2$

$Ca(OH{)}_2\rightleftharpoons C{a}^{2+}+2O{H}^{-}$

$Fe{\left(H{C}_2{O}_4\right)}_2\rightleftharpoons F{e}^{2+}+2H{C}_2{O}_4^{-}$

$2H{C}_2{O}_4^{-}\rightleftharpoons 2H^{+}+C_2{O}_4^{2-}$

One mole of $Fe{\left(H{C}_2{O}_4\right)}_2$ will furnish 2 mole of $H^{+}$ which require 1 mole of $Ca(OH{)}_2$

It is not a redox reaction it is rather a neutralisation reaction.