Question

How many moles of lead (II) chloride will be formed from a reaction between $6.5g$ of $PbO$ and $3.2g$ of $HCl$ ?

• A. 0.339
• B. 0.011
• C. 0.029
• D. 0.044

Answer 1

Answer: (C)

Mole of $PbO=\frac{6.5}{223}=0.029$
Mole of $HCl=\frac{3.2}{36.5}=0.087$
Since, $1$ mole of PbO reacts with $2$ moles of $HCl$, thus in this reaction $PbO$ is the limiting reagent.
Hence, $1$ mole of $PbO$ forms $=1$ mole of $PbC{l}_2$ $0.029$ mole of $PbO$ will form $=0.029$ mole of $PbC{l}_2$