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Q.
How many moles of lead (II) chloride will be formed from a reaction between $6.5 \,g$ of $PbO$ and $3.2 \,g$ of $HCl$ ?
AIPMTAIPMT 2008Some Basic Concepts of Chemistry
Solution:
Mole of $PbO =\frac{6.5}{223}=0.029$
Mole of $HCl =\frac{3.2}{36.5}=0.087$
Since, $1$ mole of PbO reacts with $2$ moles of $HCl$, thus in this reaction $PbO$ is the limiting reagent.
Hence, $1$ mole of $PbO$ forms $=1$ mole of $PbCl _{2}$ $0.029$ mole of $PbO$ will form $=0.029$ mole of $PbCl _{2}$