How many moles of KMnO4 will be needed to react completely with one mole of ferrous oxalate (.FeC2O4.) in acidic solution?

Question

How many moles of KMnO4 will be needed to react completely with one mole of ferrous oxalate (.FeC2O4.) in acidic solution? (A) (2/5) (B) (1/5) (C) (3/5) (D) (2/3)

Tardigrade Admin · Accepted Answer

3MnO4-+5FeC2O4+24H+ arrow 3Mn2 ++5Fe3 ++10CO2+12H2O Number of mole of KMnO4 required per mole of FeC2O4=(3/5)

Q. How many moles of $K M n O_{4}$ will be needed to react completely with one mole of ferrous oxalate $(F e C_{2} O_{4})$ in acidic solution?

$\frac{2}{5}$

$\frac{1}{5}$

$\frac{3}{5}$

$\frac{2}{3}$

$3 M n O_{4}^{-} + 5 F e C_{2} O_{4} + 24 H^{+} \to 3 M n^{2 +} + 5 F e^{3 +} + 10 C O_{2} + 12 H_{2} O$
Number of mole of $K M n O_{4}$ required per mole of $F e C_{2} O_{4} = \frac{3}{5}$

Q. How many moles of KMnO4​ will be needed to react completely with one mole of ferrous oxalate (FeC2​O4​) in acidic solution?

52​

51​

53​

32​