Question

How many moles of $KMnO_{4}$ will be needed to react completely with one mole of ferrous oxalate $\left(\right.FeC_{2}O_{4}\left.\right)$ in acidic solution?

• A. $\frac{2}{5}$
• B. $\frac{1}{5}$
• C. $\frac{3}{5}$
• D. $\frac{2}{3}$

Answer 1

Answer: (C)

$3MnO_{4}^{-}+5FeC_{2}O_{4}+24H^{+} \rightarrow 3Mn^{2 +}+5Fe^{3 +}+10CO_{2}+12H_{2}O$
Number of mole of $KMnO_{4}$ required per mole of $FeC_{2}O_{4}=\frac{3}{5}$