Question

How many moles of acidified $FeS{O}_4$ can be completely oxidised by one mole of $KMn{O}_4$ ?

• A. 10
• B. 5
• C. 6
• D. 2

Answer 1

Answer: (B)

The balanced equation of acidified
$FeS{O}_4$ with $KMn{O}_4$ is $2KMn{O}_4+8H_{2}S{O}_4\underset{ferroussulphate}{+10FeS{O}_4}\to$
$K_{2}S{O}_4+2MnS{O}_4\underset{ferricsulphate}{+5F{e}_2{(S{O}_4)}_3+}8H_{2}O$
$\because$ 2 mole of KMn04 oxidised = 10 moles of $FeS{O}_4$ $\therefore$ 1 mole of KMn04 will oxidise $=\frac{10}{2}=5$ moles of $FeS{O}_4$