How many grams of ice at 0 oC can be melted by the addition of 500 J of heat? (The molar heat of fusion for ice is 6.02 kJmol- 1 )

Question

How many grams of ice at 0 oC can be melted by the addition of 500 J of heat? (The molar heat of fusion for ice is 6.02 kJmol- 1 ) (A) 0.083 g (B) 1.50 g (C) 3.06 g (D) 12.0 g

Tardigrade Admin · Accepted Answer

As 6020 J is required to melt 18 g of ice at 0oC So, 1 J would melt =(18/6020)g of ice at 0 oC ≈ 3× 10- 3g Hence 500 J would melt =500× 3× 10- 3 g of ice at 0 oC = 1.5 g

Q. How many grams of ice at $0^{o} C$ can be melted by the addition of 500 J of heat? (The molar heat of fusion for ice is $6.02 k J m o l^{- 1}$ )

0.083 g

1.50 g

3.06 g

12.0 g

As 6020 J is required to melt 18 g of ice at 0oC

So, 1 J would melt $= \frac{18}{6020} g$ of ice at $0^{o} C$ $\approx 3 \times 1 0^{- 3} g$

Hence 500 J would melt $= 500 \times 3 \times 1 0^{- 3}$ g of ice at $0^{o} C$ $=$ 1.5 g

Q. How many grams of ice at 0oC can be melted by the addition of 500 J of heat? (The molar heat of fusion for ice is 6.02kJmol−1 )