How many gram of sodium (atomic mass 23 u) is required to prepare one mole of ethane from methyl chloride by Wurtz reaction?

Question

How many gram of sodium (atomic mass 23 u) is required to prepare one mole of ethane from methyl chloride by Wurtz reaction? (A) 2 (B) 23 (C) 11.5 (D) 46

Tardigrade Admin · Accepted Answer

The Wurtz reaction between methyl chloride and sodium metal in presence of dry ether can be written as: 2CH3Cl+2Na xrightarrow textDry ether underset textEthaneCH3 —CH3+2NaCl ⇒ 2 moles of sodium metal reacts to give 1 mole of ethane. Also, 1 mole of Na metal =23 g ∴ 2 moles of Na metal =23 × 2=46 g Thus, 46 g of sodium is required to prepare one mole of ethane from methyl chloride by Wurtz reaction

Q. How many gram of sodium (atomic mass $23 u$ ) is required to prepare one mole of ethane from methyl chloride by Wurtz reaction?

$2$

$23$

$11.5$

$46$

Q. How many gram of sodium (atomic mass 23u) is required to prepare one mole of ethane from methyl chloride by Wurtz reaction?

2

23

11.5

46

Q. How many gram of sodium (atomic mass $23 u$ ) is required to prepare one mole of ethane from methyl chloride by Wurtz reaction?

$2$

$23$

$11.5$

$46$