Question

How many faradays are required to reduce $1$ mol of $Mn{O}_4^{-}$ to $M{n}^{2+}$?

• A. $1$
• B. $2$
• C. $3$
• D. $5$

Answer 1

Answer: (D)

$8H^{+}\underset{(1mole)}{+5e^{-}+}Mn{O}_4^{-}\to M{n}^{+2}+4H_{2}O$
$5$ moles of $e^{-}=5$ Faradays