Question

How many faradays are required to reduce $1$ mol of $MnO_{4}^{-}$ to $Mn^{2+}$?

• A. $1$
• B. $2$
• C. $3$
• D. $5$

Answer 1

Answer: (D)

$8H^{+} \underset{(1 mole)}{+ 5e^{-} +} MnO_{4}^{-} \to Mn^{+2} + 4H_{2}O$
$5$ moles of $e^{-} = 5$ Faradays