How many electrons per second constitute a current of one micro ampere?

Question

How many electrons per second constitute a current of one micro ampere? (A) one electron (B) 10-6 electrons (C) 106 electrons (D) 6.25 × 1012 electrons

Tardigrade Admin · Accepted Answer

q=n e (d q/d t)=i=e((d n/d t)) ⇒ ((d n/d t))=(i/e)=(10-6 A /1.6 × 10-19 C ) =6.25 × 1012 ( text electrons / text second )

Q. How many electrons per second constitute a current of one micro ampere?

one electron

$1 0^{- 6}$ electrons

$1 0^{6}$ electrons

$6.25 \times 1 0^{12}$ electrons

$q = n e$
$\frac{d q}{d t} = i = e (\frac{d n}{d t})$
$\Rightarrow (\frac{d n}{d t}) = \frac{i}{e} = \frac{1 0 ^{- 6} A}{1.6 \times 1 0 ^{- 19} C}$
$= 6.25 \times 1 0^{12} \frac{electrons}{second}$

Q. How many electrons per second constitute a current of one micro ampere?

one electron

10−6 electrons

106 electrons

6.25×1012 electrons

q=ne dtdq​=i=e(dtdn​) ⇒(dtdn​)=ei​=1.6×10−19C10−6A​ =6.25×1012 second electrons ​

$1 0^{- 6}$ electrons

$1 0^{6}$ electrons

$6.25 \times 1 0^{12}$ electrons

$q = n e$
$\frac{d q}{d t} = i = e (\frac{d n}{d t})$
$\Rightarrow (\frac{d n}{d t}) = \frac{i}{e} = \frac{1 0 ^{- 6} A}{1.6 \times 1 0 ^{- 19} C}$
$= 6.25 \times 1 0^{12} \frac{electrons}{second}$