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Q. How many electrons per second constitute a current of one micro ampere?

Current Electricity

Solution:

$q=n e$
$\frac{d q}{d t}=i=e\left(\frac{d n}{d t}\right)$
$\Rightarrow \left(\frac{d n}{d t}\right)=\frac{i}{e}=\frac{10^{-6} A }{1.6 \times 10^{-19} C }$
$ =6.25 \times 10^{12} \frac{\text { electrons }}{\text { second }}$