How many coulombs of electricity are consumed when 100 mA current is passed through a solution of AgNO3 for half an hour during an electrolysis experiment?

Question

How many coulombs of electricity are consumed when 100 mA current is passed through a solution of AgNO3 for half an hour during an electrolysis experiment? (A) 108 (B) 18000 (C) 180 (D) 3000

Tardigrade Admin · Accepted Answer

Q=i × t Here, i=100 m A=(1/10)-A i=(1/2) h=(1/2) × 60 × 60=1800 s Q=(1/10) × 1800=180 C

Q. How many coulombs of electricity are consumed when $100 m A$ current is passed through a solution of $A g N O_{3}$ for half an hour during an electrolysis experiment?

108

18000

180

3000

$Q = i \times t$
Here, $i = 100 m A = \frac{1}{10} - A$
$i = \frac{1}{2} h = \frac{1}{2} \times 60 \times 60 = 1800 s$
$Q = \frac{1}{10} \times 1800 = 180 C$

Q. How many coulombs of electricity are consumed when 100mA current is passed through a solution of AgNO3​ for half an hour during an electrolysis experiment?

108

18000

180

3000

Q=i×t Here, i=100mA=101​−A i=21​h=21​×60×60=1800s Q=101​×1800=180C

Q. How many coulombs of electricity are consumed when $100 m A$ current is passed through a solution of $A g N O_{3}$ for half an hour during an electrolysis experiment?

$Q = i \times t$
Here, $i = 100 m A = \frac{1}{10} - A$
$i = \frac{1}{2} h = \frac{1}{2} \times 60 \times 60 = 1800 s$
$Q = \frac{1}{10} \times 1800 = 180 C$