How long will a passenger sitting at the window of a train travelling at a speed of 54 kmh-1 see a train,passing by in the opposite direction with a speed of 36 kmh-1 , if the length of the second train is 150 m?

Question

How long will a passenger sitting at the window of a train travelling at a speed of 54 kmh-1 see a train,passing by in the opposite direction with a speed of 36 kmh-1 , if the length of the second train is 150 m? (A) 10 s (B) 6 s (C) 6 min (D) 8 min

Tardigrade Admin · Accepted Answer

Relative speed of 1st train w.r.t. IInd = (54 + 36) kmh-1 = 90 × (5/18) ms-1 = 25 ms-1 Time duration to pass IInd train = (150/25) = 6 s

Q. How long will a passenger sitting at the window of a train travelling at a speed of 54 km $h^{- 1}$ see a train,passing by in the opposite direction with a speed of 36 km $h^{- 1}$ , if the length of the second train is 150 m?

10 s

6 s

6 min

8 min

Relative speed of 1st train w.r.t. IInd
$= (54 + 36) km h^{- 1} = 90 \times \frac{5}{18} m s^{- 1}$
$= 25 m s^{- 1}$
Time duration to pass IInd train
$= \frac{150}{25} = 6 s$

Q. How long will a passenger sitting at the window of a train travelling at a speed of 54 kmh−1 see a train,passing by in the opposite direction with a speed of 36 kmh−1 , if the length of the second train is 150 m?

10 s

6 s

6 min

8 min

Relative speed of 1st train w.r.t. IInd =(54+36)kmh−1=90×185​ms−1 =25ms−1 Time duration to pass IInd train =25150​=6s

Q. How long will a passenger sitting at the window of a train travelling at a speed of 54 km $h^{- 1}$ see a train,passing by in the opposite direction with a speed of 36 km $h^{- 1}$ , if the length of the second train is 150 m?

Relative speed of 1st train w.r.t. IInd
$= (54 + 36) km h^{- 1} = 90 \times \frac{5}{18} m s^{- 1}$
$= 25 m s^{- 1}$
Time duration to pass IInd train
$= \frac{150}{25} = 6 s$