Question

$\mathrm{HOOC}-(\mathrm{CH}{}_2){}_4-\mathrm{COOH}+2\mathrm{C}{}_2\mathrm{H}{}_5\mathrm{OH}\underset{\mathrm{Toluene}}{\overset{\mathrm{H}{}_2\mathrm{SO}{}_4}{\to }}\mathrm{C}{}_2\mathrm{H}{}_5\mathrm{OOC}-\mathrm{CH}{}_2-\mathrm{COOC}\mathrm{H}{}_5$
The purpose of using toluene here is

• A. to make both substances (acid & alcohol) miscible
• B. that the product is insoluble in toluene
• C. that the reactants are insoluble in water
• D. because of the formation of low boiling azotrope

Answer 1

Answer: (A)

Toluene is used in the reaction to make both substances (acid and alcohol) miscible.