Homolytic fission of the following alkanes form free radicals CH3 -CH3, CH3 -CH2 -CH3, (CH3)2 CH - CH3, CH3 - CH2 - CH (CH3)2. Increasing order of Stability of the radicals is :

Question

Homolytic fission of the following alkanes form free radicals CH3 -CH3, CH3 -CH2 -CH3, (CH3)2 CH - CH3, CH3 - CH2 - CH (CH3)2. Increasing order of Stability of the radicals is : (A) (CH3)2 dotC-CH2CH3 < CH3- dotC -CH3< CH3 dotCH2 < (CH3)3 dotC (B) CH3- dotCH2 < CH3- dotCH -CH3< (CH3)2 dotC-CH2CH3 < (CH3)3 dotC (C) CH3- dotCH2 < CH3- dotCH -CH3 <(CH3)3 dotC< (CH3)2 dotC-CH2CH3 (D) (CH3)3 dotC< (CH3)2 dotC-CH2CH3< CH3- dotCH -CH3 < CH3- dotCH2

Tardigrade Admin · Accepted Answer

Correct answer is (b) CH3- dotCH2 < CH3- dotCH -CH3< (CH3)2 dotC-CH2CH3 < (CH3)3 dotC

Q. Homolytic fission of the following alkanes form free radicals $C H_{3} - C H_{3}, C H_{3} - C H_{2} - C H_{3}, (C H_{3})_{2} C H - C H_{3}, C H_{3} - C H_{2} - C H (C H_{3})_{2}$ . Increasing order of Stability of the radicals is :

$(C H_{3})_{2} \dot{C} - C H_{2} C H_{3} < C H_{3} - \dot{C} - C H_{3} < C H_{3} \dot{C} H_{2} < (C H_{3})_{3} \dot{C}$

$C H_{3} - \dot{C} H_{2} < C H_{3} - \dot{C} H - C H_{3} < (C H_{3})_{2} \dot{C} - C H_{2} C H_{3} < (C H_{3})_{3} \dot{C}$

$C H_{3} - \dot{C} H_{2} < C H_{3} - \dot{C} H - C H_{3} < (C H_{3})_{3} \dot{C} < (C H_{3})_{2} \dot{C} - C H_{2} C H_{3}$

$(C H_{3})_{3} \dot{C} < (C H_{3})_{2} \dot{C} - C H_{2} C H_{3} < C H_{3} - \dot{C} H - C H_{3} < C H_{3} - \dot{C} H_{2}$

Correct answer is (b) $C H_{3} - \dot{C} H_{2} < C H_{3} - \dot{C} H - C H_{3} < (C H_{3})_{2} \dot{C} - C H_{2} C H_{3} < (C H_{3})_{3} \dot{C}$

Q. Homolytic fission of the following alkanes form free radicals CH3​−CH3​,CH3​−CH2​−CH3​,(CH3​)2​CH−CH3​,CH3​−CH2​−CH(CH3​)2​. Increasing order of Stability of the radicals is :

(CH3​)2​C˙−CH2​CH3​<CH3​−C˙−CH3​<CH3​C˙H2​<(CH3​)3​C˙

CH3​−C˙H2​<CH3​−C˙H−CH3​<(CH3​)2​C˙−CH2​CH3​<(CH3​)3​C˙

CH3​−C˙H2​<CH3​−C˙H−CH3​<(CH3​)3​C˙<(CH3​)2​C˙−CH2​CH3​

(CH3​)3​C˙<(CH3​)2​C˙−CH2​CH3​<CH3​−C˙H−CH3​<CH3​−C˙H2​