HNO3 oxidises NH+4 ions to nitrogen and itself gets reduced to NO2. The moles of HNO3 required by 1 mole of (NH4)2SO4 is:

Question

HNO3 oxidises NH+4 ions to nitrogen and itself gets reduced to NO2. The moles of HNO3 required by 1 mole of (NH4)2SO4 is: (A) 4 (B) 5 (C) 6 (D) 2

Tardigrade Admin · Accepted Answer

HNO3 + NH4+ → N2 + NO2 V.F. of HNO3 = (5 - 4) = 1 V.F. of NH4+ = [0 - (-3)] = 3 so molar ratio of HNO3 and NH4+ is 3: 1. 1 mole (NH4)2SO4 is found to contain 2 mole of NH4+

Q. $H N O_{3}$ oxidises $N H_{4}^{+}$ ions to nitrogen and itself gets reduced to $N O_{2} .$ The moles of $H N O_{3}$ required by $1 m o l e$ of $(N H_{4}) 2_{S} O_{4}$ is:

$4$

$5$

$6$

$2$

Q. HNO3​ oxidises NH4+​ ions to nitrogen and itself gets reduced to NO2​. The moles of HNO3​ required by 1mole of (NH4​)2S​O4​ is:

4

5

6

2

HNO3​+NH4+​→N2​+NO2​ V.F.ofHNO3​=(5−4)=1 V.F.ofNH4+​=[0−(−3)]=3 so molar ratio of HNO3​ and NH4+​is3:1. 1 mole (NH4​)2​SO4​ is found to contain 2 mole of NH4+​ HNO3​ is 3×2=6 moles

Q. $H N O_{3}$ oxidises $N H_{4}^{+}$ ions to nitrogen and itself gets reduced to $N O_{2} .$ The moles of $H N O_{3}$ required by $1 m o l e$ of $(N H_{4}) 2_{S} O_{4}$ is:

$4$

$5$

$6$

$2$