Hinsberg’s reagent is

Question

Hinsberg’s reagent is (A) (CH3CO)2 O/pyridine (B) C6H5SO2Cl (C) C6H5SO2NH2 (D) CH3COCl/pyridine

Tardigrade Admin · Accepted Answer

Hinsberg's reagent is benzene sulphonyl chloride ( C 6 H 5 SO 2 Cl ). It is used to test for and distinguish between primary, secondary and tertiary amines.

Q. Hinsberg’s reagent is

$(C H_{3} CO)_{2}$ O/pyridine

$C_{6} H_{5} S O_{2} Cl$

$C_{6} H_{5} S O_{2} N H_{2}$

$C H_{3} COCl /$ pyridine

Hinsberg's reagent is benzene sulphonyl chloride $(C_{6} H_{5} S O_{2} Cl)$ .

It is used to test for and distinguish between primary, secondary and tertiary amines.

Q. Hinsberg’s reagent is

(CH3​CO)2​ O/pyridine

C6​H5​SO2​Cl

C6​H5​SO2​NH2​

CH3​COCl/pyridine

Hinsberg's reagent is benzene sulphonyl chloride (C6​H5​SO2​Cl). It is used to test for and distinguish between primary, secondary and tertiary amines.

$(C H_{3} CO)_{2}$ O/pyridine

$C_{6} H_{5} S O_{2} Cl$

$C_{6} H_{5} S O_{2} N H_{2}$

$C H_{3} COCl /$ pyridine

Hinsberg's reagent is benzene sulphonyl chloride $(C_{6} H_{5} S O_{2} Cl)$ .

It is used to test for and distinguish between primary, secondary and tertiary amines.