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Tardigrade
Question
Chemistry
Hex-4-ene-2-ol on treatment with PCC gives 'A'. 'A' on reaction with sodium hypoiodite gives ' B ', which on further heating with soda lime gives ' C '. The compound ' C prime is
Q. Hex-
4
-ene-
2
-ol on treatment with PCC gives '
A
'. '
A
' on reaction with sodium hypoiodite gives '
B
', which on further heating with soda lime gives '
C
'. The compound '
C
′
is
433
136
JEE Main
JEE Main 2022
Alcohols Phenols and Ethers
Report Error
A
2- pentene
33%
B
proponaldehyde
12%
C
2-butene
45%
D
4-methylpent-2-ene
10%
Solution:
Correct answer is (c) 2-butene