Henry's law constants for aqueous solution of CO , O 2, CO 2 and C 2 H 2 gases are respectively at 25° C as 58 × 103, 43 × 103, 1.61 × 103 and 1.34 × 103. The solubility of these gases decreases in the order

Question

Henry's law constants for aqueous solution of CO , O 2, CO 2 and C 2 H 2 gases are respectively at 25° C as 58 × 103, 43 × 103, 1.61 × 103 and 1.34 × 103. The solubility of these gases decreases in the order (A)  CO>O2>CO2>C2H2 (B) O2>CO2>CO>C2H2 (C) C2H2>CO2>O2>CO  (D) O2>CO2>C2H2>CO

Tardigrade Admin · Accepted Answer

p=KH X; Higher the value of KH at a given pressure, the lower is the solubility of the gas in the liquid. Therefore, the solubility of the given gases decreases in the order C 2 H 2> CO 2> O 2> CO

Q. Henry's law constants for aqueous solution of $CO, O_{2}, C O_{2}$ and $C_{2} H_{2}$ gases are respectively at $2 5^{\circ} C$ as $58 \times 1 0^{3}, 43 \times 1 0^{3}, 1.61 \times 1 0^{3}$ and $1.34 \times 1 0^{3}$ . The solubility of these gases decreases in the order

$CO > O_{2} > C O_{2} > C_{2} H_{2}$

$O_{2} > C O_{2} > CO > C_{2} H_{2}$

$C_{2} H_{2} > C O_{2} > O_{2} > CO$

$O_{2} > C O_{2} > C_{2} H_{2} > CO$

$p = K_{H} X$ ; Higher the value of $K_{H}$ at a given pressure, the lower is the solubility of the gas in the liquid.
Therefore, the solubility of the given gases decreases in the order
$C_{2} H_{2} > C O_{2} > O_{2} > CO$

Q. Henry's law constants for aqueous solution of CO,O2​,CO2​ and C2​H2​ gases are respectively at 25∘C as 58×103,43×103,1.61×103 and 1.34×103. The solubility of these gases decreases in the order

CO>O2​>CO2​>C2​H2​

O2​>CO2​>CO>C2​H2​

C2​H2​>CO2​>O2​>CO

O2​>CO2​>C2​H2​>CO