Heating methyl phenyl ether with HI gives

Question

Heating methyl phenyl ether with HI gives (A) methanol + iodobenzene (B) methyl alcohol + benzyl alcohol (C) methyl iodide + phenol (D) methyl iodide + iodobenzene

Tardigrade Admin · Accepted Answer

Iodide ion attacks the smaller CH 3 group to give CH 3 I and C 6 H 3 OH that is, C 6 H 5 OCH 3 xrightarrowHIC 6 H 5 OH + CH 3 I

Q. Heating methyl phenyl ether with HI gives

methanol + iodobenzene

methyl alcohol + benzyl alcohol

methyl iodide + phenol

methyl iodide + iodobenzene

Iodide ion attacks the smaller $C H_{3}$ group to give $C H_{3} I$ and $C_{6} H_{3} O H$ that is,
$C_{6} H_{5} OC H_{3} HI C_{6} H_{5} O H + C H_{3} I$

Q. Heating methyl phenyl ether with HI gives

methanol + iodobenzene

methyl alcohol + benzyl alcohol

methyl iodide + phenol

methyl iodide + iodobenzene

Iodide ion attacks the smaller CH3​ group to give CH3​I and C6​H3​OH that is, C6​H5​OCH3​HI​C6​H5​OH+CH3​I

Iodide ion attacks the smaller $C H_{3}$ group to give $C H_{3} I$ and $C_{6} H_{3} O H$ that is,
$C_{6} H_{5} OC H_{3} HI C_{6} H_{5} O H + C H_{3} I$