Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
Heat of neutralization of CsOH with all strong acid is 13.4 kcal mol -1. The heat released on neutralization of CsOH with HF (weak acid)is 16.4 kcal mol -1 . Δ H ominus of ionization of HF is
Q. Heat of neutralization of
C
s
O
H
with all strong acid is
13.4
k
c
a
l
m
o
l
−
1
. The heat released on neutralization of
C
s
O
H
with
H
F
(weak acid)is
16.4
k
c
a
l
m
o
l
−
1
.Δ
H
⊖
of ionization of
H
F
is
274
141
Thermodynamics
Report Error
A
3.0
k
c
a
l
B
−
3.0
k
c
a
l
C
6.0
k
c
a
l
D
0.3
k
c
a
l
Solution:
H
⊕
+
O
⊖
H
⟶
H
2
O
Δ
H
1
=
−
13.4
k
c
a
l
O
⊖
H
+
H
F
⟶
H
2
O
+
F
⊖
Δ
H
2
=
−
16.4
k
c
a
l
H
F
⟶
H
⊕
+
F
⊖
Δ
H
1
=
?
Δ
H
3
=
Δ
H
2
−
Δ
H
1
=
−
16.4
−
(
−
13.4
)
=
−
3.0
k
c
a
l