Heat required to melt 1kg ice into water at 0∘C=80kcal. Heat required to raise temperature of 1kg water from 0∘C to 100∘C . =mS⋅Δt=(1kg)×(1kcalkg−1∘C)×(100−0) =100kcal
Heat required to convert 1kg boiling water into steam at 100∘C =mL=1kg×540kcalg−1=540kcal
Thus, total heat required to convert 1kg of ice at 0∘C into steam at 100∘C =80+100+540=720kcal