Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
HCN+H2O arrow [X]+NH3 text, [X] arrow [Y]+H2O (U n b a l a n c e d e q u a t i o n s) [Y] May be prepared by which one of the following methods?
Q.
H
CN
+
H
2
O
→
[
X
]
+
N
H
3
,
[
X
]
→
[
Y
]
+
H
2
O
(
U
nba
l
an
ce
d
e
q
u
a
t
i
o
n
s
)
[Y] May be prepared by which one of the following methods?
1917
227
NTA Abhyas
NTA Abhyas 2020
The d-and f-Block Elements
Report Error
A
By dehydration of Malonic acid with
P
2
O
5
B
By thermal decomposition of carbon sub-oxide in air.
C
By heating potassium hexacyanoferrate (II) with conc.
H
2
S
O
4
.
D
By the action of conc.
H
N
O
3
on charcoal.
Solution:
H
CN
+
2
H
2
O
→
H
COO
H
(
X
)
+
2
N
H
3
;
H
COO
H
→
Δ
CO
[
Y
]
+
H
2
O
(iii) Only
K
4
(
F
e
(
CN
)
6
)
gives
CO
with conc.
H
2
S
O
4
according to the following reaction.
K
4
[
F
e
(
CN
)
6
]
+
6
H
2
S
O
4
(
co
n
c
.
)
+
6
H
2
O
→
2
K
2
S
O
4
+
F
e
S
O
4
+
3
(
N
H
4
)
2
S
O
4
+
6
CO
(i) Malonic acid gives
C
3
O
2
;
(ii)
C
3
O
2
gives
C
O
2
.
(iv) Action of conc.
H
N
O
3
on charcoal gives
C
O
2
.