HBr reacts with CH2=CH-OCH3 under anhydrous conditions at room temperature to give -

Question

HBr reacts with CH2=CH-OCH3 under anhydrous conditions at room temperature to give - (A) BrCH2-CH2-OCH3 (B) H3C-CHBr-OCH3 (C) CH3CHO and CH3Br (D) BrCH2CHO and CH3OH

Tardigrade Admin · Accepted Answer

Methyl vinyl ether under anhydrous conditions at room temperature undergoes addition reaction.

C H_{2} = C H - OC H_{3} \to H B r C H_{3} - B r ∣ C H - O - C H_{3}

The reaction takes place according to markovnikov's rule.

Q. HBr reacts with $C H_{2} = C H - OC H_{3}$ under anhydrous conditions at room temperature to give -

$B r C H_{2} - C H_{2} - OC H_{3}$

$H_{3} C - C H B r - OC H_{3}$

$C H_{3} C H O an d C H_{3} B r$

$B r C H_{2} C H O an d C H_{3} O H$

Methyl vinyl ether under anhydrous conditions at room temperature undergoes addition reaction.
$C H_{2} = C H - OC H_{3} \to H B r C H_{3} - B r ∣ C H - O - C H_{3}$
The reaction takes place according to markovnikov's rule.

Q. HBr reacts with CH2​=CH−OCH3​ under anhydrous conditions at room temperature to give -

BrCH2​−CH2​−OCH3​

H3​C−CHBr−OCH3​

CH3​CHOandCH3​Br

BrCH2​CHOandCH3​OH