Half litre each of three samples of H2O2 labelled 10 vol, 15 vol, 20 vol are mixed and then diluted with 1700 ml of water. Calculate relative strength of resultant H2O2 solution

Question

Half litre each of three samples of H2O2 labelled 10 vol, 15 vol, 20 vol are mixed and then diluted with 1700 ml of water. Calculate relative strength of resultant H2O2 solution (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Volume strength of H2O2 = 5.6 × N 10 Vol. H2O2 =(10/5.6) N H2O2 15 Vol. H2O2 =(15/5.6) N H2O2 20 Vol. H2O2 =(20/5.6) N H2O2 Let 500 mL of each is mixed then total volume of mixture = 1500 mL Also this is diluted with 1700 ml, so total volume becomes 3200 ml N × 3200=(10 ×500/5.6) + (15 ×500/5.6) +(20 ×500/5.6) or NH2O2 mixture = (500 ×45/5.6 ×3200) =1.255 ∴ Vol. strength of H2O2 =1.255 ×5.6 =7.03

Q. Half litre each of three samples of H2​O2​ labelled 10vol,15vol,20vol are mixed and then diluted with 1700 ml of water. Calculate relative strength of resultant H2​O2​ solution

Q. Half litre each of three samples of $H_{2} O_{2}$ labelled $10 v o l, 15 v o l, 20 v o l$ are mixed and then diluted with $1700$ ml of water. Calculate relative strength of resultant $H_{2} O_{2}$ solution