Half-life period of a first order reaction is 1386 s. The specific rate constant of the reaction is

Question

Half-life period of a first order reaction is 1386 s. The specific rate constant of the reaction is (A) 5.0 × 10-3 s-1 (B) 0.5 × 10-2 s-1 (C) 0.5 × 10-3 s-1 (D) 5.0 × 10-2 s-1

Tardigrade Admin · Accepted Answer

K =(0.693/ t 1 / 2)=(0.693/1386)=0.5 × 10-3 S -1

Q. Half-life period of a first order reaction is $1386 s .$ The specific rate constant of the reaction is

$5.0 \times 1 0^{- 3} s^{- 1}$

$0.5 \times 1 0^{- 2} s^{- 1}$

$0.5 \times 1 0^{- 3} s^{- 1}$

$5.0 \times 1 0^{- 2} s^{- 1}$

$K = \frac{0.693}{t _{1/2}} = \frac{0.693}{1386} = 0.5 \times 1 0^{- 3} S^{- 1}$

Q. Half-life period of a first order reaction is 1386s. The specific rate constant of the reaction is

5.0×10−3s−1

0.5×10−2s−1

0.5×10−3s−1

5.0×10−2s−1