H2S is passed into one nm3 of a solution containing 0.1 mole of Zn2+ and 0.01 mole of Cu2+ till the sulphide ion concentration reaches 8.1 ×10 -19 moles. Which one of the following statements is true? [Ksp of ZnS and CuS are 3 × 10-22 and 8 × 10-36 respectively

Question

H2S is passed into one nm3 of a solution containing 0.1 mole of Zn2+ and 0.01 mole of Cu2+ till the sulphide ion concentration reaches 8.1 ×10 -19 moles. Which one of the following statements is true? [Ksp of ZnS and CuS are 3 × 10-22 and 8 × 10-36 respectively (A) Only ZnS precipitates (B) Both CuS and ZnS precipitate (C) Only CuS precipitates (D) No precipitation occurs

Tardigrade Admin · Accepted Answer

The ionic product for ZnS (0.1 × 8.1 × 10-19) and for CuS (0.01 × 8.1 × 10-19) exceeds their Ksp values. Hence, both get precipitated.

Only $Z n S$ precipitates

Both $C u S$ and $Z n S$ precipitate

Only $C u S$ precipitates

No precipitation occurs

The ionic product for $Z n S (0.1 \times 8.1 \times 1 0^{- 19})$ and for CuS $(0.01 \times 8.1 \times 1 0^{- 19})$ exceeds their $K_{s p}$ values. Hence, both get precipitated.

Q. H2​S is passed into one nm3 of a solution containing 0.1 mole of Zn2+ and 0.01 mole of Cu2+ till the sulphide ion concentration reaches 8.1×10−19 moles. Which one of the following statements is true? [Ksp​ of ZnS and CuS are 3×10−22 and 8×10−36 respectively

Only ZnS precipitates

Both CuS and ZnS precipitate

Only CuS precipitates

No precipitation occurs

The ionic product for ZnS(0.1×8.1×10−19) and for CuS (0.01×8.1×10−19) exceeds their Ksp​ values. Hence, both get precipitated.

Only $Z n S$ precipitates

Both $C u S$ and $Z n S$ precipitate

Only $C u S$ precipitates

The ionic product for $Z n S (0.1 \times 8.1 \times 1 0^{- 19})$ and for CuS $(0.01 \times 8.1 \times 1 0^{- 19})$ exceeds their $K_{s p}$ values. Hence, both get precipitated.