H 2 S contains 94.11 % sulphur; SO 2 contains 50 % oxygen and H 2 O contains 11.11 % hydrogen. Thus,

Question

H 2 S contains 94.11 % sulphur; SO 2 contains 50 % oxygen and H 2 O contains 11.11 % hydrogen. Thus, (A) Law of multiple proportion is followed (B) Law of reciprocal proportion is followed (C) Law of conservation of mass is followed (D) All of the above

Tardigrade Admin · Accepted Answer

H 2 S 5.89 g H combines with =94.11 gS Hence, 1 g H combines with =16 g S SO 2 50 g O combine with =50 g S Hence, 1 g O combines with =1 g S H 2 O 11.11 g H combines with =88.89 g O 1 g H combine with =8 g O Thus, law of reciprocal proportion is followed

Q. $H_{2} S$ contains $94.11%$ sulphur; $S O_{2}$ contains $50%$ oxygen and $H_{2} O$ contains $11.11%$ hydrogen. Thus,

Law of multiple proportion is followed

Law of reciprocal proportion is followed

Law of conservation of mass is followed

All of the above

$H_{2} S 5.89 g$ H combines with $= 94.11 g S$
Hence, $1 g$ H combines with $= 16 g S$
$S O_{2} 50 g$ O combine with $= 50 g S$
Hence, $1 g O$ combines with $= 1 g S$
$H_{2} O 11.11 g H$ combines with $= 88.89 g O$
$1 g H$ combine with $= 8 g O$
Thus, law of reciprocal proportion is followed

Q. H2​S contains 94.11% sulphur; SO2​ contains 50% oxygen and H2​O contains 11.11% hydrogen. Thus,