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  4. H 2 S contains 94.11 % sulphur; SO 2 contains 50 % oxygen and H 2 O contains 11.11 % hydrogen. Thus,

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Q. $H _2 S$ contains $94.11 \%$ sulphur; $SO _2$ contains $50 \%$ oxygen and $H _2 O$ contains $11.11 \%$ hydrogen. Thus,

Some Basic Concepts of Chemistry

Solution:

$H _2 S 5.89\, g$ H combines with $=94.11\, gS$
Hence, $1 \, g$ H combines with $=16 \, g\, S$
$SO _2 50 \, g$ O combine with $=50\, g\, S$
Hence, $1 \, g \,O$ combines with $=1 \, g\, S$
$H _2 \, O 11.11\, g \, H$ combines with $=88.89\, g \, O$
$1 \, g \, H$ combine with $=8\, g\, O$
Thus, law of reciprocal proportion is followed