H 2 S 2 O 8 and H 2 SO 5 both have +6 oxidation state of sulphur. It is due to

Question

H 2 S 2 O 8 and H 2 SO 5 both have +6 oxidation state of sulphur. It is due to (A) Presence of peroxy group (B) Presence of superoxo group (C) Presence of neutral O 2 (D) Presence of ozone

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Correct answer is (a) Presence of peroxy group

Q. $H_{2} S_{2} O_{8}$ and $H_{2} S O_{5}$ both have $+ 6$ oxidation state of sulphur. It is due to

Presence of peroxy group

Presence of superoxo group

Presence of neutral $O_{2}$

Presence of ozone

Correct answer is (a) Presence of peroxy group

Q. H2​S2​O8​ and H2​SO5​ both have +6 oxidation state of sulphur. It is due to

Presence of peroxy group

Presence of superoxo group

Presence of neutral O2​

Presence of ozone

Correct answer is (a) Presence of peroxy group

Q. $H_{2} S_{2} O_{8}$ and $H_{2} S O_{5}$ both have $+ 6$ oxidation state of sulphur. It is due to

Presence of neutral $O_{2}$