Gravitational potential V versus distance r graph is represented in the figure. The magnitude of gravitational field intensity is equal to

Question

Gravitational potential V versus distance r graph is represented in the figure. The magnitude of gravitational field intensity is equal to <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-2hk6bunsacl6.png" /> (A) 8 N/Kg (B) 4 N/Kg (C) 6 N/Kg (D) 2 N/Kg

Tardigrade Admin · Accepted Answer

| vecE|=(Δ V/Δ r)=(8-4/(1) sin 30°)=8 mathrmNkg-1

Q. Gravitational potential $V$ versus distance $r$ graph is represented in the figure. The magnitude of gravitational field intensity is equal to

$8 N / K g$

$4 N / K g$

$6 N / K g$

$2 N / K g$

$∣ E ∣ = \frac{Δ V}{Δ r} = \frac{8 - 4}{( 1 ) s i n 3 0 ^{\circ}} = 8 Nkg^{- 1}$

Q. Gravitational potential V versus distance r graph is represented in the figure. The magnitude of gravitational field intensity is equal to

8N/Kg

4N/Kg

6N/Kg

2N/Kg